4.9t^(2)+2t-950=0

Solution for 4.9t^(2)+2t-950=0 equation:

4.9t^(2)+2t-950=0

a = 4.9; b = 2; c = -950;
Δ = b2-4ac
Δ = 22-4·4.9·(-950)
Δ = 18624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18624}=\sqrt{64*291}=\sqrt{64}*\sqrt{291}=8\sqrt{291}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8\sqrt{291}}{2*4.9}=\frac{-2-8\sqrt{291}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8\sqrt{291}}{2*4.9}=\frac{-2+8\sqrt{291}}{9.8}
$